2x^2-7x=26

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Solution for 2x^2-7x=26 equation:



2x^2-7x=26
We move all terms to the left:
2x^2-7x-(26)=0
a = 2; b = -7; c = -26;
Δ = b2-4ac
Δ = -72-4·2·(-26)
Δ = 257
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{257}}{2*2}=\frac{7-\sqrt{257}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{257}}{2*2}=\frac{7+\sqrt{257}}{4} $

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